2=-16x^2+64x+6

Solution for 2=-16x^2+64x+6 equation:

2=-16x^2+64x+6

We move all terms to the left:

2-(-16x^2+64x+6)=0

We get rid of parentheses

16x^2-64x-6+2=0

We add all the numbers together, and all the variables

16x^2-64x-4=0

a = 16; b = -64; c = -4;
Δ = b2-4ac
Δ = -642-4·16·(-4)
Δ = 4352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4352}=\sqrt{256*17}=\sqrt{256}*\sqrt{17}=16\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-16\sqrt{17}}{2*16}=\frac{64-16\sqrt{17}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+16\sqrt{17}}{2*16}=\frac{64+16\sqrt{17}}{32}
$